电子测量技术第二版林占江课后答案培训课件 习题解答1.1答电子测量是以电子技术理论为依据，以电子测量仪器和设备为手段，以电量和非电量为测量对象的测量过程。 属于电子测量的是 （2）、 （3）。 1.2答见1.2节与1.3节。 1.3答主基准、副基准和工作基准。 第第1章绪论第第2章测量误差分析与数据处理2.1绝对误差0.05V修正值-0.05V实际相对误差1.01%示值相对误差1.00%电压表应定为0.5级2.215V,2.5级2.310%2.4绝对误差-0.2mA；修正值0.2mA实际相对误差0.25%0.5级:2.514.8V,40.8%2.61.15V,0.99V;23%,19.8%2.75%,0.42dB2.8200k,266.7k,25%2.9200k,199.973k,0.014%2.10微差法、替代法、零示法2.112.5级2.121000.82125,0.0472.130.99260.00082.14正态分布,1215.016.11,2.1586.4,3.18,0.00312,5.84E42.163.3,382.17mA+nB,9.5%2.184%2.191600.16%,9.41.0%,2.205%,5%2.212级第第4章数字测量方法4.1见P1154.2见P1194.3见P1154.44位，4位半，3位半，3位半，0.01mV4.50.005%,4.60.0008V,8个字4.70.000058V,0.0032%,0.0000418,0.023%4.8见P1354.9见P1434.100.00002%,0.0002%,0.002%4.111.01s4.12100kHz4.1375s4.14P1444.150.05%,20%4.160.056%4.17100kHz,40s,104.189.4ns4.19用外触发方式4.20滞后电源电压45超前455.1,5.2参阅本间相关内容5.3李沙育图形，是圆形。 5.4李沙育图形 （1）椭圆形 （2）“8”字形5.5被测信号频率与扫描信号频率不成整数倍，图形向左“跑动”。 5.6被测信号频率与扫描信号频率不成整数倍，波形紊乱。 5.7前沿有上冲，前沿弯曲。 5.8最小周期T=0.2s1010=20s,频率50k5.9最高工作频率是20MHz5.10最低工作频率是0.4Hz5.110.02s/cm5.1240ms，3ms，29ms5.13 （1）聚焦不良 （2）回扫消隐失效5.14引入50Hz交流电源的干扰5.15参阅本章相关内容第第5章时域测量第第6章频域测量6.1P2046.2P2056.3P2086.4P2086.5P2126.6P2146.7P2236.8P2216.9P2246.10P2236.11P2266.12P233第第7章逻辑分析仪7.1P2367.2P2377.3P2387.4P2417.5P2437.6P2467.7P2497.8P265第第8章调制域测量8.1P2708.2P2728.3P2728.4P2748.5P2758.6P2768.7P277第第9章非电量测量9.1P2799.2P2809.3P2819.4P2829.5P2829.6P2859.7P2869.8P2879.9P291第第10章电磁兼容测量10.1P29510.2P29710.3P29810.4P29910.5P30510.6P30810.7P307第第11章智能仪器11.1P31011.2P31111.3P31411.4P316第第12章虚拟仪器12.1P31912.2P32112.3P32512.4P33312.5P33612.6P338第第13章自动测试系统13.1P33913.2P34113.3P34213.4P34613.5P34713.6P349。 内容仅供参考