找题目录1 int fun(_1_ *std)2 void WriteText(FILE _1_)3 fprintf(_1_,%d %fn,i,sqrt(double)i);4 if(fs=fopen(source, _1_)=NULL)5 s-data=_1_;6 t=t-_1_;7 free(_1_);8 while(p!=_1_)9 _1_=0;10 s+= p-_1_;11_1_ fun(STU *std, char *num)12 if( _1_=year)13 void modify(_1_ *ss,float a)14 void fun(PERSON _1_)15 max= _1_;16 void show(STU _1_)17 for(j=_1_; j=a)_1_(chb) ? (bc? b :(ac?c:_1_)31 n=_1_;32 while(tnext=_1_;49 ai=_1_;50 _1_ = 0;1填空，(1) STYPE(2) FILE (3) fp改错 (1) for(i = 0 ; i ai.s)j=0; bj+=ai; min=ai.s;else if(min=ai.s)bj+=ai;return j;3填空,(1) fp(2) fclose(fp)(3) fname改错(1) for(i=j+1;idata (3) t改错 (1) fun (char *a) (2) printf(%c,*a);编程int i;char *p=s, *q=t;int n=0,m=0;while(*p) n+;p+;while(*q) m+;q+;if(n=m) p=s;elsep=t;return p;7填空，(1) q (2) next (3) next改错 (1) p=j;(2) p=i;编程int i,j=0;*n=0;for(i=1;i=a& ssi0) (2) else if(k=0)编程 int i,j;for(i=0; iam) m=k;编程 unsigned t,s=0,s1=1,p=0; t=w; while(t10) if(t/10) p=t%10; s=s+p*s1; s1=s1*10; t=t/10; return s;17填空,(1) i+1 (2) k=j (3) t改错 (1) void fun(char *str, char ch )(2) if(*str!=ch) (3) str1 = 0;编程 char bN;int i=0, j;memset(b, 0, N);for(j=strlen(s)-1; j=0; j-)bi+=sj;strcpy(s, b);18填空，(1) k, (2) len (3) ssij改错 (1) result*=(double)n; (2) return result;编程char *p=s;int i=0;while(*p)if(*p !=c)si+=*p;p+; si=0;19填空，(1) ssi,(2) n+j (3) 1改错 (1) if(*p= )(2) *(p-1)=toupper(*(p-1);编程char t;int i,j;for(i=1;i=0&k=0.000001) xn=xn*x*(0.5-n+1)/n; n+=1; sn+=xn; return(sn);24填空，(1) 1,(2) 1 (3) i改错 (1) k=i;(2) c=k;编程 int i;double avg=0.0, sum=0.0, abs=0.0, fc;for (i=0;i1 & n0)编程 if(ai.s=eps) pi+=s; t=n/(2*n+1);s*=t; n+;pi=pi*2; return pi;37填空(1) 1 (2) 2*i (3) (-1)改错(1) k+; (2) if(m=k)编辑 int i;*max=a0;*d=0; for(i=1; i (3) (2*i+1)改错(1) double fun(int n) (2) s=s+(double)a/b;编程 int i, j, max=a00;for(i=0; i=n) aj=t; return j;44填空(1) rb (2) (3) fwrite改错(1) p=s; (2) while(*p+);编程int i, j ; for(i = 0 ; i 10) bM - 1+ ; else bj+ ; 45填空(1) filename (2) fp (3) fp改错(1) p=(NODE *)malloc(sizeof(NODE); (2) return h;编程int i,n=0; for(i=0;i=a&si=0&sidata (3) p-next改错(1) int i, one=0, zero=0;(2) switch( si ) (3) case 0:zero+;break;编程 while(*s)*a=*s;s+; a+; *a=0;49填空(1) 0 (2) t (3) i+t改错(1) bi=0; (2) bai - a+;(3) if (bmax aij )编程double sum=0,max,min;int i;max=min=a0;for(i=0;iai)min=ai;sum=sum-max-min;return(sum/(n-2);