主讲人：黄明桂主讲人：黄明桂Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.利用初中所学过的知识，说说这是怎样的 图形？课题导入 轴对称 图形中心对称 图形Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.xy0Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.xy0Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.新课讲授 请从对称的角度对下列函数进行分类 .（分组合作完成）OxyOxyxyOxyOxyoEvaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.xyx-x数学中的对称图像 ：xy1xy1xy1-1xyEvaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.练习：根据下列函数图象,判断函数奇偶性.yxyxyxyxy(xR )(xR)(xR)(xR)Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.(1)(2)(3 )(4 )偶函数非奇非偶函数奇函数非奇非偶函数练习：判断下列函数的奇偶性ooooxxxxyyyyy0yx偶函数yx0y是奇函数也是偶函数(5 )(6 )函数按是否有奇偶性可分为四类Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.结论结论 一 (等量） -5-4-3 -2-1 0 1 2 3 4 52.函数值对应表结论三：对定义域内任 意一个自变量x ，都有 f（-x）=f（x）25 169410149 1625Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.结论结论 一 -5-4 -3 -2 -1 0 1 2 3 4 52.函数值对应表结论三：对定义域内任 意一个自变量x ，都有 f（-x）=-f（x）-5 -4 -3 -2-1012 345Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.偶函数的定义一般地，如果对于函 数f(x)的定义域内的任意 一个x，都有 f(-x)=f(x), 那么称函数y=f(x)偶函数 .奇偶性定义 奇函数的定义一般地，如果对于函 数f(x)的定义域内的任意 一个x，都有 f(-x)=-f(x), 那么称函数y=f(x)奇函数 . 如果函数如果函数f(x)是奇函数或者是偶函 数，我们就说函数f(x)具有奇偶性Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.（1 1）图像法）图像法（2 2）定义法）定义法Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.例例2.2.判断下列函数的奇偶性判断下列函数的奇偶性：Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.用定义法判断函数奇偶性解题步骤:(1)先确定函数定义域,并判断 定义域是否关于原点对称;(2)求f(-x)，找 f(x)与f(-x)的关系; 若f(-x)=f(x),则f(x)是偶函数; 若f(-x)= - f(x),则f(x)是奇函数.(3)作出结论.f(x)是偶函数或奇函数或非奇非偶函 数或即是奇函数又是偶函数。给出函数给出函数判断定义域判断定义域 是否对称是否对称结论结论是是f(-x)f(-x)与与f(x)f(x)否否Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.巩固练习巩固练习变式变式Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.ABDEA1B1C1D1E1CH Oxy1、 已知函数 y=f(x) 是偶函数，它在y轴右边的图象如下图所示，画出函数 y=f(x) 在y轴左边的图象。课课堂堂练习练习Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd.2、已知函数 y=f(x) 是奇函数，它在y轴右边的图象如下图所示，画出函数 y=f(x) 在y轴左边的图象。OxyABC