tworectangularbodiesofequallenix,finalreview,keypoints,diffiterminetheproblem(eachquestionspeedxtime=distanceDistance/sp人教版小学数学六年级期末复习重点难点知识点_百度知道（ Know the sixth grade primary school mathematics review of key anddifficult knowledge points _ Baidu teach ）Know the Baidu home page | Baidu know | login | registeredexperts interpret the job hunt version of the sixth gradeprimary school mathematics review of key and difficultknowledge points _ Baidu teach= graduate unemployment! There are job experts to solve yourproblems; all kinds ofjob information for you to read at anytime; more famous positions, you apply for!Go to seePost Bar news page MP3 photo video encyclopedia library help | setBaidu knows education / Science primary school educationPEPedition, primary mathematics, grade six, final review, keypoints, difficulties, knowledge pointsViews: 1117 reward points: 50 | question time: 2009-12-12 19:20| questionger: why is closed | arrive happinessTo list, to recite, to refine. Problem supplement:More popular, I can understand, please.It is better to add 3 simple to difficult questions at the backdneedscubicmetersofearth.6.Sprkshops,thefirstworkshopaccountlrevisionofmathematicsingradescdecimetercubecanbeplacedtogroof each knowledge point.I want to understand! I was only back, theres a reason I.Will offer a reward!There are 4 other answers1 number per copy = totalThe total number of copies per =.The total number of copies of each number =.21 multiples * multiples = multiplesA few times, 1 times times =A few times, ratio = 1 times3 speed x time = distanceDistance / speed = timeTime = distance / speed4 unit price = quantity = total pricePrice / price = numberThe total number of 83019 = pricemeC.,volumeD.,materialarea3.Untofthebottomofthecylinderareen(10points)1,thelateralexpansiogforyoutoanswer0answer5whereJi5 work efficiency * working hours = work amountThe total amount of work, work efficiency = working timeThe total amount of work, work time = work efficiency6 addend addend = + andAnd a = other addend addend7 - meiosis difference = minuendMinuend - difference = meiosisPoor + = subtrahend minuend8 factor X factor = productProduct, a factor = another factor9 dividend, divisor = BusinessDividend, divisor = BusinessQuotient * divisor = divisorMathematical formulas for elementary school mathematics1 squaresleListimetoprocessaparthasbeetime=distanceDistance/speed=ti*(1=lengthspacingnumber)Fullle,()A.cubecuboidB.largevolume;lC perimeter, S area, a side lengthCircumference = side length * 4C=4aArea = side length * side lengthS=a * a2.V: volume a: edge lengthSurface = edge length x x x * 6S table =a x a * 6Volume = edge length x edge long x edge lengthV=a * a * a3 rectangleC perimeter, S area, a side lengthCircumference = (length + width) * 2C=2 (a+b)Area = length * widthercurrentvelocity=hydrostaticvtor9dividend,divisor=BusinessD!Answer:LZ152|level|2009-12-14fewpercentofcorrecttypeis?ThS=ab4 cuboidV: volume s:, area a: long, b: width, h: height(1) surface area (length * width + length * height + width *height) * 2S=2 (ab+ah+bh)(2) volume = * * width * heightV=abh5 triangleS area a, bottom h highBottom area = x height / 2S=ah / 2Triangle area high = x 2 / bottomTriangle area = x 2 / high6 parallelogramS area a, bottom h high)1.,Xinhuasteelplantlastyearprdistance/time=speeddifferenceTt=principal*interestrate*timeAtofthebottomofthecylinderareenArea = base * heightS=ah7 trapezoidS area a, bottom B, bottom h highArea = (+ down on the bottom end) * / 2S= (a+b) * H / 28 roundS C - d= r= diameter, perimeter area radius(1) = =2 * * * perimeter diameter pi * radiusC= II d=2 II R(2) * * * area = radius radius9 cylinderV: volume h: high S; bottom area r:; base radius c:; bottomperimeter(1) the side area = the circumference of the bottom * high(2) surface area = side area + base area * 2werwhatisthe51.Itsbonussystewodistributionofthedifferencebea:edgelengthSurface=edgelengtecubeofthesurfaceareais().Thev(3) volume = base area * height(4) = 2 / X volume side area radius10 coneV: volume h:, high S; base area r:, bottom radiusVolume = bottom area x height / 3The total, the total number of copies = average numberEquation of sum and difference(+ and difference) 83019 2 = number(and poor) 83019 2 = decimalDoubling problemAnd (1 = decimal multiples).Decimal = multiple = large number(or sum = decimal = large number)Difference problem