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- 原则 原则电极电势表- 在酸性溶液中(29) 电对方程式Eq/VL(I)-(0)Li+e=i3.04Cs()(0)Cs-Cs-3.02Rb()-(0)Rb+e=Rb2.98K(I)-(0)K+e=K-293B(II)(0)a2+e=a2.1Sr(I)(0)S22eSr.8a()-(0)Ca2+2-C2.868Na(I)(0)Na+e=Na2.1La(III)-(0)L3+3e-=2.379g(II)-(0)g+2-=Mg.372C(III)-(0)Ce3+3Ce-2.3(0)-(-I)H2()e-2H.2A(II)-(0)AF63el6F-2.09Th(IV)(0)Th44e-T1.8Be(II)(0)Be2+2e-=Be-1.8(II)()U33e=U1.798H(IV)(0)HO2+2+4eHf2O-74l(III)-(0)Al33e=Al1.62Ti(I)(0)i2+ei1.630Zr(IV)()24H4-=Zr+2H21.553S(V)-(0)SF62-4e-Si61.24Mn(I)(0)Mn2+e-=n-1.15Cr()-(0)Cr+2e=Cr-0913i(III)-(II)T3+e=Ti2+0.B(I)-()HBO3H+3e=B+32O9Ti(IV)(0)T2+4H+4-=T2HO-0.6T(0)(-I)Te+2+2e-He-0.9Zn(I)-(0)Zn2+2e-Zn-0.76Ta(V)-(0)a2O+10H+10=2+5HO-0.75Cr(III)(0)Cr3+3e-=Cr-04Nb(V)(0)NbO5H10e-=Nb5H20.6A()(-III)As+3+3e-=sH-0.08U(V)(III)U4e-U30.6Ga(III)-(0)a3+3e-=G.549()-()H3PO2+H+e=P+22O0.5P(III)(I)3P3H-=H3PO2+O0.49*C(IV)(III)2CO22H2eH2CO40.49F(II)()F2+-=e0.4Cr(III)(II)r3+Cr+-.407Cd(I)(0)d2+e-=Cd0.030S(0)(II)Se2H+eH2Se(q)0.39Pb(II)-()PbI2e-Pb2I-035(III)-(II)Eu3+e-=Eu2+6Pb(II)-(0)PbSO4+2-+S42-.3588In(III)(0)n3+3eIn-0.8Tl(I)-(0)Tl+e=T0.36C(I)()Co2=C.28(V)(III)H3PO4+2H+2-3H2O0.276Pb(II)()PbCl2ePb2Cl-.2675i(II)-(0)Ni+2=i0257(III)-(II)3+V2+0255G(I)-(0)H2Ge34H+4-Ge+H2O-0.82A(I)(0)AgI=AI-01524n(II)-(0)Se=Sn-0175Pb(II)-(0)P+2e=P12*C(IV)(II)O2(g)+2H+2e=OH2O-0.12(0)(III)(white)3e-=P(g)-63Hg(I)(0)g2I2e=g+-0.05(I)-(0)Fe3e-Fe007H(I)-()H+2e20.0000Ag(I)(0)AgBreAB-0.073S(I.V)(II)S4622e=2320.08Ti(V)-(II)TO2+2H+e-=T3H2O0.1S(0)-(-I)S+H+e-H2S(a).42n(V)(II)n4+en1Sb(II)()26+6-=2bH2O0.152u(II)-()u2+e=Cu5Bi(II)-(0)iCl+2+3=i+Cl-H2O.183S(I)-(IV)O2-4H2e=SO+H20.172Sb(II)-(0)SO2H+3e-=SbH2O0.1Ag(I)(0)AgCl+-=Ag+C-0.2223As(I)(0)HAsO2+3H+3e-=As+H2O0.24H(I)(0)g2Cl22e-2g+2Cl-(饱和K)0.26808B(III)-(0)O+H+3e-=Bi+H2O0.20U(VI)-(IV)UO2H+2e-=4+H2O032C(I)(III)HCO+2H+2e(CN)2+2H20.3V(IV)(II)VO+He-V3HO.37Cu(I)(0)u2+2e=C.341Re(II)(0)ReO4+8H+7e-=Re+H2O0.3Ag(I)()g2Cr+e-2g+CrO42-0.4470S(V)-()HSO344e-=S3H2O0.44C(I)-(0)Cu=Cu0521I(0)(-I)I22e-=2I-0.355I(0)(I)I-+2e3I.536s(V)(III)AsO+H+2eHAsOH2O0.50Sb()-(I)Sb2O5+6H+4e-=2SO+3HO0.581Te(I)(0)Te2+4He-Te+22O0.59U(V)-(IV)UOH+e=U4+2H2O0.12*Hg(II)-(I)HC2e=Hg2l2+2Cl0.63Pt(IV)(II)PC6-+2e-=PtCl42-Cl-08()-(-)O2H+eH2O2.9Pt(I)-(0)Ptl4-2e-=Pt+4Cl055*Se(IV)-(0)SeO4H+4e=S3H2074Fe(III)(I)Fe3+e=e2+0.771H(I)(0)H2+2e-2Hg0.79A()-()ge-=Ag7996O(VIII)(0)Os48H+8e=s+408N()(IV) 2NO34H+2e-=N2O4+2O 0.03(II)-(0)2+e-Hg.851i(IV)(0)(uartz)SiO+4H+4e-Si2H2O0.87(I)(I)Cu2+eCuI.86N(III)(I)2HNO24H+4e-=H22O2H2O0.8Hg(II)-(I)2Hg+2-=Hg22+.920N(V)(II)NO3-3+2-HNO2+H2O0.934(II)-()Pd2e-d.91N()-(II)O-+4H+3e-=NO+2H2O0.957N(II)(I)HNO2H+e=NO+H2O983I(I)()IO+H2e-=I-+HO.987V()()V2+2H+e-=O2+H2O099V(V)(IV)(OH)42H+eV+3H10A(I)-(0)AuCl3e=A+4Cl-1.002e(I)(IV)H6T+2H+2-=TeO+4H2O.02N(I)-()N44H+4e=2NO+2H21.035(I)(I)N2+2H+2e=2NO21.65I(V)(-I)IO-6H+e-321.085Br(0)(-I)Br2(aq)2e-=2r-1.083(VI)-(IV)SeO42-4H=H2Se3H2.51Cl(V)-(IV)CO-2HeClO2O.1P(I)-(0)Pt2+2ePt1.18l(II)(V)O-+2H+2=lO3-H2O19I()(0)2IO+2H+1eH2O15Cl(V)-(II)ClH+2e=HCO2H2O1.24M(IV)(I)O2+4+e=Mn2+H24O()-(I)2+H+4e-2H2.229l(II)(I)T1+2Tl+1.252C(IV)-(II)ClO2H+eHClO21.277N(III)()2HN+4H4eN2+32O1.27*r(I)-(III)Cr2O72-+1+6e-=Cr3+72O1.B()-(-I)HBO+H2e=
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