O/S =Average Front Door O/S Handle Lever Return Spring Load : MAverage Front Door Pawl Return Spring Moment : MP/S Average Front Door Return Spring Force : P=7.15N2a=30g(m/s )W 1=0.035kgW2=0.0135kgW3=0.010kgW 4=0.008kgW 5=0.020kgL1=5mmL2=40mmL3=95mmL4=8mmL5=65mmL6=20mm L7=7mmL8=28mmL9=20mmL10=18mmL 11=1.5mmL15=30mmF= ma = W/g X 30g = 30W(kg) = 294.3W(N)F1= 294.3W 1 = 294.3 X 0.0351 = 10.33(N)F2= 294.3W 2xL2/L3=Mopen =F1 L1 =51.65N -mmM close =F 2L4+M o/s=1.67 X8+367=380.36N mmMopen-M close =51.65-380.36=-328.71N mm Force tending to ope n Latch is con sidered as zero because it can not be tra nsmited to PawlF3= 294.3W 3x(L 5-L15)/L 5=F4= 294.3W 2-F2 = = 2.3(N)F5= 294.3W 5 = = 5.89(N)F6= 294.3W 4 = = 2.35(N)F7= (F 3xL6+F6xL7+F4xL6-PxL 8)/L9=(1.58x20+2.35x7+2.3x20-7.15x28)/20=-5.31(N) ;System is not affected by F7.(F 7 0 , F = 0)Force(F 7) tending to open Latch is considered as zero because it can not be transmited to Pawl.Mopen=F7xL10+F6xL11=0x18+Mclose=MP/S M open -M close = 3.53-120=-116.47(N.mm) I/S=0.364N.m =364N.mmAverage Front Door I/S Handle Return Spring Moment : M Average Front Door Return Sprign Force : P=7.15N a=30g(m/s2)W6=0.020kgL12=15mmL8=28mmW7=0.010kgL13=20mmL19=24mmW 8=0.005kgL14=1.5mmL18=15mmL16=22mmL17=5mmF= ma = W/g X 30g = 30W(kg) = 294.3W(N)F8= 294.3W 6 = 294.3 X 0.020 = 5.89(N)F9= 294.3W 7 = 294.3 X 0.010 = 2.94(N)F6=( F8 X L12-F9XL14- MI/S)/L12= (5.89X15-F10=294.3W8 = 294.3 X 0.005 = 1.47(N)F11=(F6XL16+F10XL17)/L18 =(-18.67X22+1.47X5)/15 = -26.89(N) ;System is not affected by F 11.(F11 0 , F11 = 0) Force(F 7) tending to open Latch is considered as zero because it can not be transmited to Pawl.M open=( F 11 xL 19-PxL 8)/L9xL10=(0x24-7.15x28)/20x18=-180.18(N.mm).M close= M P/S M open -M close = -180.18-120=-300.18(N.mm)