.wd.第二章习题解答P36-6(1)是09组成的数字串(2)最左推导:最右推导:P36-7G(S)P36-8文法：最左推导:最右推导:语法树：/*/P36-9句子iiiei有两个语法树：P36-10/*/P36-11/*L1:L2:L3:L4:*/第三章习题参考答案P647(1)XYX1234Y5 0 1 1 0 1 1确定化：01X1,2,31,2,32,32,3,42,32,32,3,42,3,42,3,52,3,42,3,52,32,3,4,Y2,3,4,Y2,3,52,3,4, 0320 1 01 0 0 1 1 0654 0 1 0 1 1 1最小化： 002 1 1 0 0 1 0543 0 1 0 1 1 1P648(1) (2)(3)P6412(a) a10 a,b a确定化：ab00,110,10,1110给状态编号：ab012112203333 a10 a a b b b32 b a最小化： a a210 b ba b(b)032 b b a a b a a b541 b a a a已经确定化了,进展最小化最小化：021 b b a a baP6414 (1) 010 1 0(2):YX2 0 1Y1X 0确定化：01X,1,Y1,Y21,Y1,Y221,Y给状态编号：01012112213333 010 0 1 032 1 1 1 0最小化： 0310 1 1 1 0 0第四章P811(1) 按照T,S的顺序消除左递归递归子程序：procedure S;beginif sym=a or sym= then abvanceelse if sym=( then beginadvance;T;if sym=) then advance;else error; endelse errorend;procedure T;beginS;end;procedure ;beginif sym=, then beginadvance;S;endend;其中:sym:是输入串指针IP所指的符号advance:是把IP调至下一个输入符号error:是出错诊察程序(2)FIRST(S)=a,(FIRST(T)=a,(FIRST()=,FOLLOW(S)=),#FOLLOW(T)=)FOLLOW()=)预测分析表a(),#ST是LL(1)文法P812文法：(1)FIRST(E)=(,a,b,FIRST(E)=+,FIRST(T)=(,a,b,FIRST(T)=(,a,b,FIRST(F)=(,a,b,FIRST(F)=*,FIRST(P)=(,a,b,FOLLOW(E)=#,)FOLLOW(E)=#,)FOLLOW(T)=+,),#FOLLOW(T)=+,),#FOLLOW(F)=(,a,b,+,),#FOLLOW(F)=(,a,b,+,),#FOLLOW(P)=*,(,a,b,+,),#(2)考虑以下产生式:FIRST(+E)FIRST()=+=FIRST(+E)FOLLOW(E)=+#,)=FIRST(T)FIRST()=(,a,b,=FIRST(T)FOLLOW(T)=(,a,b,+,),#=FIRST(*F)FIRST()=*=FIRST(*F)FOLLOW(F)=*(,a,b,+,),#=FIRST(E)FIRST(a)FIRST(b)FIRST()=所以,该文法式LL(1)文法.(3)+*()ab#EETTFFP(4)procedure E;beginif sym=( or sym=a or sym=b or sym= then begin T; E end else errorendprocedure E;beginif sym=+ then begin advance; E end else if sym) and sym# then errorendprocedure T;beginif sym=( or sym=a or sym=b or sym= then begin F; T end else errorendprocedure T;beginif sym=( or sym=a or sym=b or sym= then T else if sym=* then errorendprocedure F;beginif sym=( or sym=a